Subtract Time Units

Subtract time units from a date time vector.

dtt_subtract_units(x, n = 1L, units = dtt_units(x))

dtt_subtract_years(x, n = 1L)

dtt_subtract_months(x, n = 1L)

dtt_subtract_days(x, n = 1L)

dtt_subtract_hours(x, n = 1L)

dtt_subtract_minutes(x, n = 1L)

dtt_subtract_seconds(x, n = 1L)

Arguments

x

A date/time vector.

n

An integer of the number of units.

units

A string of the time units. The possible values are "secs", "minutes", "hours", "days" or "weeks".

Value

The modified date time vector.

See also

dtt_add_units()

Examples

dtt_subtract_units(as.Date("1999-12-31"), 2L, "days")
#> [1] "1999-12-29"