Model Averaging SSDs

ssdtools Team

2024-10-24

Background

Many authors have noted that there is no guiding theory in ecotoxicology to justify any particular distributional form for the SSD other than that its domain be restricted to the positive real line (Newman et al. 2000), (Zajdlik 2005), (Chapman et al. 2007), (David R. Fox 2016). Indeed, (Chapman et al. 2007) described the identification of a suitable probability model as one of the most important and difficult choices in the use of SSDs. Compounding this lack of clarity about the functional form of the SSD is the omnipresent, and equally vexatious issue of small sample size, meaning that any plausible candidate model is unlikely to be rejected (D. R. Fox et al. 2021). The ssdtools R package uses a model averaging procedure to avoid the need to a-priori select a candidate distribution and instead uses a measure of ‘fit’ for each model to compute weights to be applied to an initial set of candidate distributions. The method, as applied in the SSD context is described in detail in (D. R. Fox et al. 2021), and potentially provides a level of flexibility and parsimony that is difficult to achieve with a single SSD distribution.

(D. Fox et al. 2022)

Preliminaries

Before we jump into model averaging and in particular, SSD Model Averaging, let’s backup a little and consider why we average and the advantages and disadvantages of averaging.

The pros and cons of averaging

We’re all familiar with the process of averaging. Indeed, averages are pervasive in everyday life - we talk of average income; mean sea level; average global temperature; average height, weight, age etc. etc. So what’s the obsession with averaging? It’s simple really - it’s what statisticians call data reduction which is just a fancy name to describe the process of summarising a lot of raw data using a small number of (hopefully) representative summary statistics such as the mean and the standard deviation. Clearly, it’s a lot easier to work with just a single mean than all the individual data values. That’s the upside. The downside is that the process of data reduction decimates your original data - you lose information in the process. Nevertheless, the benefits tend to outweigh this information loss. Indeed, much of ‘conventional’ statistical theory and practice is focused on the mean. Examples include T-tests, ANOVA, regression, and clustering. When we talk of an ‘average’ we are usually referring to the simple, arithmetic mean:$$\bar{X}=\frac{1}{n}\sum\limits_{i=1}^{n}{{{X}_{i}}}$$ although we recognize there are other types of mean including the geometric mean, the harmonic mean and the weighted mean. The last of these is particularly pertinent to model averaging.

Weighted Averages

For the simple arithmetic mean, all of the individual values receive the same weighting - they each contribute $\frac{1}{n}$ to the summation. While this is appropriate in many cases, it’s not useful when the components contribute to varying degrees. An example familiar to ecotoxicologists is that of a time-varying concentration as shown in the figure below.

From the figure we see there are 5 concentrations going from left to to right: $\left\{ 0.25,0.95,0.25,0.12,0.5 \right\}$. If we were to take the simple arithmetic mean of these concentrations we get $\bar{X}=0.414$. But this ignores the different durations of these 5 concentrations. Of the 170 hours, 63 were at concentration 0.25, 25 at concentration 0.95, 23 at concentration 0.25, 23 at concentration 0.12, and 36 at concentration 0.50. So if we were to weight these concentrations by time have:
$${{{\bar{X}}}_{TW}}=\frac{\left( 63\cdot 0.25+25\cdot 0.95+23\cdot 0.25+23\cdot 0.12+36\cdot 0.50 \right)}{\left( 63+25+23+23+36 \right)}=\frac{56.01}{170}=0.33$$
So, our formula for a weighted average is:$$\bar{X}=\sum\limits_{i=1}^{n}{{{w}_{i}}{{X}_{i}}}$$ with $0\le {{w}_{i}}\le 1$ and $\sum\limits_{i=1}^{n}{{{w}_{i}}=1}$.
Note, the simple arithmetic mean is just a special case of the weighted mean with $\sum\limits_{i=1}^{n}{{{w}_{i}}=\frac{1}{n}}$ ; $\forall i=1,\ldots ,n$

Model Averaging

The weighted average acknowledges that the elements in the computation are not of equal ‘importance’. In the example above, this importance was based on the proportion of time that the concentration was at a particular level. Bayesians are well-versed in this concept - the elicitation of prior distributions for model parameters provides a mechanism for weighting the degree to which the analysis is informed by existing knowledge versus using a purely data-driven approach. Model averaging is usually used in the context of estimating model parameters or quantities derived from a fitted model - for example an EC50 derived from a C-R model. Let’s motivate the discussion using the following small dataset of toxicity estimates for some chemical.

#>  [1] 1.73 0.57 0.33 0.28 0.30 0.29 2.15 0.80 0.76 0.54 0.42 0.83 0.21 0.18 0.59

Now, suppose we have only two possibilities for fitting an SSD - both lognormal distributions. Model 1 is the LN(-1.067,0.414) distribution while Model 2 is the LN(-0.387,0.617) distribution. A plot of the empirical cdf and Models 1 and 2 is shown below.

Emprirical cdf (black); Model 1(green); and Model 2 (blue)

We see that Model 1 fits well in the lower, left region and poorly in the upper region, while the reverse is true for Model 2. So using either Model 1 or Model 2 is going to result in a poor fit overall. However, the obvious thing to do is to combine both models. We could just try using 50% of Model 1 and 50% of Model 2, but that may be sub-optimal. It turns out that the best fit is obtained by using 44% of Model 1 and 56% of Model 2. Redrawing the plot and adding the weighted average of Models 1 and 2 is shown below.

Empirical cdf (black); Model 1(green); Model 2 (blue); and averaged Model (red)

Clearly the strategy has worked - we now have an excellent fitting SSD. What about estimation of an HC20? It’s a simple matter to work out the individual HC20 values for Models 1&2 using the appropriate qlnorm() function in R. Thus we have:

# Model 1 HC20
cat("Model 1 HC20 =", qlnorm(0.2, -1.067, 0.414))
#> Model 1 HC20 = 0.2428209

# Model 2 HC20
cat("Model 2 HC20 =", qlnorm(0.2, -0.387, 0.617))
#> Model 2 HC20 = 0.4040243

What about the averaged distribution? An intuitively appealing approach would be to apply the same weights to the individual HC20 values as was applied to the respective models. That is 0.44*0.2428209 + 0.56*0.4040243 = 0.33.

So our model-averaged HC20 estimate is 0.33. As a check, we can determine the fraction affected at concentration = 0.33 - it should of course be 20%. Let’s take a look at the plot.

Something’s wrong - the fraction affected at concentration 0.33 is 30% - not the required 20%. This issue is taken up in the next section

Model Averaged SSDs

As we’ve just seen, applying the model weights to component HCx values and summing does not produce the correct result. The reason for this can be explained mathematically as follows (if your not interested in the mathematical explanation - skip ahead to the next section).

The fallacy of weighting individual HCx values

The correct expression for a model-averaged SSD is: $$G\left( x \right) = \sum\limits_{i = 1}^k {{w_i}} {F_i}\left( x \right)$$ where ${F_i}\left( \cdot \right)$ is the i^th component SSD (i.e. cdf) and w_i is the weight assigned to ${F_i}\left( \cdot \right)$.
Notice that the function $G\left( x \right)$ is a proper cumulative distribution function (cdf) which means for a given quantile, x, $G\left( x \right)$ returns the cumulative probability: $$P\left[ {X \leqslant x} \right]$$

Now, the incorrect approach takes a weighted sum of the component inverse cdf’s, that is:

$$H\left( p \right) = \sum\limits_{i = 1}^k {{w_i}} {F_i}^{ - 1}\left( p \right)$$ where ${F_i}^{ - 1}\left( \cdot \right)$ is the i^th inverse cdf. Notice that ${G_i}\left( \cdot \right)$ is a function of a quantile and returns a probability while ${H_i}\left( \cdot \right)$ is a function of a probability and returns an quantile.

Now, the correct method of determining the HCx is to work with the proper model-averaged cdf $G\left( x \right)$. This means finding the inverse function ${G^{ - 1}}\left( p \right)$. We’ll address how we do this in a moment.

The reason why $H\left( p \right)$ does not return the correct result is because of the implicit assumption that the inverse of $G\left( x \right)$ is equivalent to $H\left( p \right)$. This is akin to stating the inverse of a sum is equal to the sum of the inverses i.e. $$\sum\limits_{i = 1}^n {\frac{1}{{{X_i}}}} = \frac{1}{{\sum\limits_{i = 1}^n {{X_i}} }}{\text{ ???}}$$

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For the mathematical nerds: There are some very special cases where the above identity does in fact hold, but for that you need to use complex numbers.

For example, consider two complex numbers $${\text{a = }}\frac{{\left( {5 - i} \right)}}{2}{\text{ and }}b = - 1.683 - 1.915i$$ It can be shown that $$\frac{1}{{a + b}} = \frac{1}{a} + \frac{1}{b} = 0.126 + 0.372i$$

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Back to the issue at hand, and since we’re not dealing with complex numbers, it’s safe to say:$${G^{ - 1}}\left( p \right) \ne H\left( p \right)$$

If you need a visual demonstration, we can plot $G\left( x \right)$ and the inverse of $H\left( p \right)$ both as functions of x (a quantile) for our two-component lognormal distribution above.

Clearly, the two functions are not the same and thus HCx values derived from each will nearly always be different (as indicated by the positions of the vertical red and green dashed lines in the Figure above corresponding to the 2 values of the HC20). (Note: The two curves do cross over at a concentration of about 1.12 corresponding to the 90^th percentile, but in the region of ecotoxicological interest, there is no such cross-over and so the two approaches will always yield different HCx values with this difference → 0 as x → 0).

We next discuss the use of a model-averaged SSD to obtain the correct model-averaged HCx.

Computing a model-averaged HCx

A proper HCx needs to satisfy what David Fox refers to as the inversion principle.

More formally, the inversion principle states that an HCx (denoted as ${\varphi _x}$) must satisfy the following:

$$df\left( {{\varphi _x}} \right) = x\quad \quad and\quad \quad qf\left( x \right) = {\varphi _x}$$

where $df\left( \cdot \right)$ is a model-averaged distribution function (i.e. SSD) and $qf\left( \cdot \right)$ is a model-averaged quantile function. For this equality to hold, it is necessary that $qf\left( p \right) = d{f^{ - 1}}\left( p \right)$.

So, in our example above, the green curve was taken to be $qf\left( x \right)$ and this was used to derive ${\varphi _x}$ but the fraction affected $\left\{ { = df\left( {{\varphi _x}} \right)} \right\}$ at ${\varphi _x}$ is computed using the red curve.

In ssdtools the following is a check that the inversion principle holds:

# Obtain a model-averaged HCx using the ssd_hc() function
hcp<-ssd_hc(x, p = p)
# Check that the inversion principle holds
ssd_hp(x, hcp, multi_est = TRUE) == p   # this should result in logical `TRUE`

Note: if the multi_est argument is set to FALSE the test will fail.

The inversion principle ensures that we only use a single distribution function to compute both the HCx and the fraction affected. Referring to the figure below, the HCx is obtained from the MA-SSD (red curve) by following the → arrows while the fraction affected is obtained by following the ← arrows.

Finally, we’ll briefly discuss how the HCx is computed in R using the same method as has been implemented in ssdtools.

Computing the HCx in R/ssdtools

Recall, our MA-SSD was given as $$G\left( x \right) = \sum\limits_{i = 1}^k {{w_i}} {F_i}\left( x \right)$$ and an HCx is obtained from the MA-SSD by essentially working ‘in reverse’ by starting at a value of $x$ on the vertical scale in the Figure above and following the → arrows and reading off the corresponding value on the horizontal scale.

Obviously, we need to be able to ‘codify’ this process in R (or any other computer language).
Mathematically this is equivalent to seeking a solution to the following equation:$${x:G\left( x \right) = p}$$ or, equivalently:$$x:G\left( x \right) - p = 0$$ for some fraction affected, $p$.

Finding the solution to this last equation is referred to as finding the root(s) of the function $G\left( x \right)$ or, as is made clear in the figure below, finding the zero-crossing of the function $G\left( x \right)$ for the case $p=0.2$.

In R finding the roots of $x:G\left( x \right) - p = 0$ is achieved using the uniroot() function.

Help on the uniroot function can be found here

Where do the model-averaged weights come from?

This is a little more complex, although we’ll try to provide a non-mathematical explanation. For those interested in going deeper, a more comprehensive treatment can be found in (Burnham and Anderson 2002) and (Fletcher 2018).

This time, we’ll look at fitting a gamma, lognormal, and pareto distribution to our sample data:

#>  [1] 1.73 0.57 0.33 0.28 0.30 0.29 2.15 0.80 0.76 0.54 0.42 0.83 0.21 0.18 0.59

The adequacy (or otherwise) of a fitted model can be assessed using a variety of numerical measures known as goodness-of-fit or GoF statistics. These are invariably based on a measure of discrepancy between the emprical data and the hypothesized model. Common GoF statistics used to test whether the hypothesis of some specified theoretical probability distribution is plausible for a given data set include: Kolmogorov-Smirnov test; Anderson-Darling test; Shapiro-Wilk test;and Cramer-von Mises test. The Cramer-von Mises test is a good choice and is readily performed using the cvm.test() function in the goftest package in R as follows:

dat <- data.frame(Conc = c(1.73, 0.57, 0.33, 0.28, 0.3, 0.29, 2.15, 0.8, 0.76, 0.54, 0.42, 0.83, 0.21, 0.18, 0.59))
library(goftest)
library(EnvStats) # this is required for the Pareto cdf (ppareto)

# Examine the fit for the gamma distribution (NB: parameters estimated from the data)
cvm.test(dat$Conc, null = "pgamma", shape = 2.0591977, scale = 0.3231032, estimated = TRUE)

# Examine the fit for the lognormal distribution (NB: parameters estimated from the data)
cvm.test(dat$Conc, null = "plnorm", meanlog = -0.6695120, sd = 0.7199573, estimated = TRUE)

# Examine the fit for the Pareto distribution (NB: parameters estimated from the data)
cvm.test(dat$Conc, null = "ppareto", location = 0.1800000, shape = 0.9566756, estimated = TRUE)

    Cramer-von Mises test of goodness-of-fit
    Braun's adjustment using 4 groups
    Null hypothesis: Gamma distribution
    with parameters shape = 2.0591977, scale = 0.3231032
    Parameters assumed to have been estimated from data

data:  dat$Conc
omega2max = 0.34389, p-value = 0.3404


    Cramer-von Mises test of goodness-of-fit
    Braun's adjustment using 4 groups
    Null hypothesis: log-normal distribution
    with parameter meanlog = -0.669512
    Parameters assumed to have been estimated from data

data:  dat$Conc
omega2max = 0.32845, p-value = 0.3719


    Cramer-von Mises test of goodness-of-fit
    Braun's adjustment using 4 groups
    Null hypothesis: distribution ‘ppareto’
    with parameters location = 0.18, shape = 0.9566756
    Parameters assumed to have been estimated from data

data:  dat$Conc
omega2max = 0.31391, p-value = 0.4015

From this output and using a level of significance of $p = 0.05$, we see that none of the distributions is implausible. However, if forced to choose just one distribution, we would choose the Pareto distribution (smaller values of the omega2max statistic are better). However, this does not mean that the gamma and lognormal distributions are of no value in describing the data. We can see from the plot below, that in fact both the gamma and lognormal distributions do a reasonable job over the range of toxicity values. The use of the Pareto may be a questionable choice given it is truncated at 0.18 (which is the minimum value of our toxicity data).

Emprirical cdf (black); lognormal (green); gamma (blue); and Pareeto (red)

As in the earlier example, we might expect to find a better fitting distribution by combining all three distributions using a weighted SSD. The issue we face now is how do we choose the weights to reflect the relative fits of the three distributions? Like all tests of statistical significance, a p-value is computed from the value of the relevant test statistic - in this case, the value of the omega2max test statistic. For this particular test, it’s a case of the smaller the better. From the output above we see that the omega2max values are $0.344$ for the gamma distribution, $0.328$ for the lognormal distribution, and $0.314$ for the Pareto distribution.

We might somewhat naively compute the relative weights as:
${w_1} = \frac{{{{0.344}^{ - 1}}}}{{\left( {{{0.344}^{ - 1}} + {{0.328}^{ - 1}} + {{0.314}^{ - 1}}} \right)}} = 0.318$         ${w_2} = \frac{{{{0.328}^{ - 1}}}}{{\left( {{{0.344}^{ - 1}} + {{0.328}^{ - 1}} + {{0.314}^{ - 1}}} \right)}} = 0.333$     and ${w_3} = \frac{{{{0.314}^{ - 1}}}}{{\left( {{{0.344}^{ - 1}} + {{0.328}^{ - 1}} + {{0.314}^{ - 1}}} \right)}} = 0.349$
   (we use reciprocals since smaller values of omega2max represent better fits). As will be seen shortly - these are incorrect.

However, being based on a simplistic measure of discrepancy between the observed and hypothesized distributions, the omega2max statistic is a fairly ‘blunt instrument’ and has no grounding in information theory which is the basis for determining the weights that we seek.

A discussion of information theoretic methods for assessing goodness-of-fit is beyond the scope of this vignette. Interested readers should consult (Burnham and Anderson 2002). A commonly used metric to determine the model-average weights is the Akaike Information Criterion or AIC. The formula for the $AIC$ is: $$AIC = 2k - 2\ln \left( \ell \right)$$ where $k$ is the number of model parameters and $\ell$ is the likelihood for that model. Again, a full discussion of statistical likelihood is beyond the present scope. A relatively gentle introduction can be found here.

The likelihood for our three distributions can be computed in R as follows:

sum(log(dgamma(dat$Conc, shape = 2.0591977, scale = 0.3231032)))
#> [1] -7.020597
sum(log(dlnorm(dat$Conc, meanlog = -0.6695120, sdlog = 0.7199573)))
#> [1] -5.812947
sum(log(EnvStats::dpareto(dat$Conc, location = 0.1800000, shape = 0.9566756)))
#> [1] -5.621683

From which the AIC values readily follow:

#> AIC for gamma distribution = 18.04119
#> AIC for lognormal distribution = 15.62589
#> AIC for Pareto distribution = 15.24337

As with the omega2max statistic, smaller values of AIC are better. Thus, a comparison of the AIC values above gives the ranking of distributional fits (best to worst) as: Pareto > lognormal > gamma

Computing model weights from the AIC

We will simply provide a formula for computing the model weights from the AIC values. More detailed information can be found here.

The AIC for the i^th distribution fitted to the data is $$AI{C_i} = 2{k_i} - 2\ln \left( {{L_i}} \right)$$ where ${L_i}$ is the i^th likelihood and ${k_i}$ is the number of parameters for the i^th distribution. Next, we form the differences: $${\Delta _i} = AI{C_i} - AI{C_0}$$ where $AI{C_0}$ is the AIC for the best-fitting model (i.e.$AI{C_0} = \mathop {\min }\limits_i \left\{ {AI{C_i}} \right\}$ ). The model-averaged weights ${w_i}$ are then computed as

AIC Model averaging weights $${w}_{i}=\frac{\exp \left\{ -\frac{1}{2}{{\Delta }_{i}} \right\}}{\sum{\exp \left\{ -\frac{1}{2}{{\Delta }_{i}} \right\}}}$$

The model-averaged weights for the gamma, lognormal, and Pareto distributions used in the previous example can be computed ‘manually’ in R as follows:

dat <- c(1.73, 0.57, 0.33, 0.28, 0.3, 0.29, 2.15, 0.8, 0.76, 0.54, 0.42, 0.83, 0.21, 0.18, 0.59)
aic <- NULL
k <- 2 # number of parameters for each of the distributions


aic[1] <- 2 * k - 2 * sum(log(dgamma(dat, shape = 2.0591977, scale = 0.3231032))) # Gamma distribution

aic[2] <- 2 * k - 2 * sum(log(dlnorm(dat, meanlog = -0.6695120, sdlog = 0.7199573))) # lognormal distribution

aic[3] <- 2 * k - 2 * sum(log(EnvStats::dpareto(dat, location = 0.1800000, shape = 0.9566756))) # Pareto distribution

delta <- aic - min(aic) #  compute the delta values

aic.w <- exp(-0.5 * delta)
aic.w <- round(aic.w / sum(aic.w), 4)

cat(
  " AIC weight for gamma distribution =", aic.w[1], "\n",
  "AIC weight for lognormal distribution =", aic.w[2], "\n",
  "AIC weight for pareto distribution =", aic.w[3], "\n"
)

 AIC weight for gamma distribution = 0.1191 
 AIC weight for lognormal distribution = 0.3985 
 AIC weight for pareto distribution = 0.4824 

Finally, let’s look at the fitted model-averaged SSD:

Empirical cdf (black) and model-averaged fit (magenta)

As can be seen from the figure above, the model-averaged fit provides a very good fit to the empirical data.

Correcting for distributions having differing numbers of parameters

In deriving the AIC, Akaike had to make certain, strong assumptions. In addition, the bias factor (the $2k$ term) was derived from theoretical considerations (such as mathematical expectation) that relate to infinite sample sizes. For small sample sizes, the AIC is likely to select models having too many parameters (i.e models which over-fit). In 1978, Sugiura proposed a modification to the AIC to address this problem, although it too relied on a number of assumptions. This ‘correction’ to the AIC for small samples (referred to as $AI{{C}_{c}}$) is

Corrected Akaike Information Criterion (AICc) $$AI{{C}_{c}}=AIC+\frac{2{{k}^{2}}+2k}{n-k-1}$$ where n is the sample size and k is the number of parameters.

It is clear from the formula for $AI{{C}_{c}}$ that for   $n\gg k$,    $AI{{C}_{c}}\simeq AIC$. The issue of sample size is ubiquitous in statistics, but even more so in ecotoxicology where logistical and practical limitations invariably mean we are dealing with (pathologically) small sample sizes. There are no hard and fast rules as to what constitutes an appropriate sample size for SSD modelling. However, Professor David Fox’s personal rule of thumb which works quite well is:

Sample size rule-of-thumb for SSD modelling $$n\ge 5k+1$$ where n is the sample size and k is the number of parameters.

Since most of the common SSD models are 2-parameter, we should be aiming to have a sample size of at least 11. For 3-parameter models (like the Burr III), the minimum sample size is 16 and if we wanted to fit a mixture of two, 2-parameter models (eg. logNormal-logNormal or logLogistic-logLogistic) the sample size should be at least 26. Sadly, this is rarely the case in practice! Jurisdictional guidance material may specify minimum sample size requirements, and should be adhered to where available and relevant.

Model-Averaging in ssdtools

Please see the Getting started with ssdtools vignette for examples of obtaining model-averaged HCx values and predictions using ssdtools.

References

Burnham, Kenneth, and David Anderson. 2002. Model Selection and Multimodel Inference - a Practical Information-Theoretic Approach. Springer. https://link.springer.com/book/10.1007/b97636.

Chapman, PF RM, A Hart, W Roelofs, T Aldenberg, K Solomon, J LM Tarazona, P Byrne, et al. 2007. “Methods of Uncertainty Analysis.” In: A H (Ed) EUFRAM Concerted Action to Develop a European Framework for Probabilistic Risk Assessment of the Environmental Impacts of Pesticides, Vol 2, Detailed Reports on Role, Methods, Reporting and Validation.

Fletcher, David. 2018. Model Averaging. Springer. https://link.springer.com/book/10.1007/978-3-662-58541-2.

Fox, D. R., R. A. Dam, R. Fisher, G. E. Batley, A. R. Tillmanns, J. Thorley, C. J. Schwarz, D. J. Spry, and K. McTavish. 2021. “Recent Developments in Species Sensitivity Distribution Modeling.” Environmental Toxicology and Chemistry 40 (2): 293–308. https://doi.org/10.1002/etc.4925.

Fox, David R. 2016. “Contemporary Methods for Statistical Design and Analysis.” In: Blasco J, Chapman PM, Campana O, Hampel M (Eds) Marine Ecotoxicology., August. https://shop.elsevier.com/books/marine-ecotoxicology/blasco/978-0-12-803371-5.

Fox, DR, R Fisher, JL Thorley, and C Schwarz. 2022. “Joint Investigation into statistical methodologies Underpinning the derivation of toxicant guideline values in Australia and New Zealand.” Environmetrics Australia; Australian Institute of Marine Science. https://doi.org/10.25845/fm9b-7n28.

Newman, Michael C., David R. Ownby, Laurent C. A. Mézin, David C. Powell, Tyler R. L. Christensen, Scott B. Lerberg, and Britt-Anne Anderson. 2000. “Applying species-sensitivity distributions in ecological risk assessment: Assumptions of distribution type and Sufficient numbers of species.” Environmental Toxicology and Chemistry 19 (February): 508–15. https://doi.org/10.1002/etc.5620190233.

Zajdlik, B. 2005. “Statistical Analysis of the SSD Approach for Development of Canadian Water Quality Guidelines.” CCME Project 354‐200/5. Zajdlik; Associates.

Licensing

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Copyright 2021 Environment and Climate Change Canada
Copyright 2023-2024 Australian Government Department of Climate Change, Energy, the Environment and Water

The documentation is released under the CC BY 4.0 License

The code is released under the Apache License 2.0